b pi
f_average = 1/(b-a) S f(t)dt=(1)/(pi-0) S e^(-2t) * (cos(3t) + 5sin(4t))dt
a 0
OF COURSE ITS SO SIMPLE WHY DIDNT I SEE IT BEFORE?!
its equal to : ((11)/(10pi(e)^(2pi)) * (e^(2pi) - 1)
its so easy!
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